The speed of train A is equal to the speed of train B and the length of train A is 60 m more than that of train B

The speed of train A is equal to the speed of train B and the length of train A is 60 m more than that of train B. If train A crosses a pole in 15 seconds and train B crosses a pole in 12 seconds, then find the sum of the speed of trains A and B together?

A.            50 m/sec

B.            20 m/sec

C.            40 m/sec

D.            30 m/sec

E.            None of these

Sol:

Let the speed of train A = x

And the speed of train B = x

The length of train B = y

And the length of train A = y+60

y + 60 = 15 * x—(1)

y = 12 * x —(2)

From (1) and (2),

12x + 60 = 15x

3x = 60

x = 20

y + 60 = 15 * 20

y = 300 – 60

y = 240

The speed of train A = 20 m/sec

And the speed of train B = 20 m/sec

The sum of the speed of trains A and B together

= 20 + 20 = 40 m/sec

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