![The total impedance of the secondary winding, leads, and burden of a 5 A CT is 0.01 Ω. If the fault current is 20 times the rated primary current of the CT](https://www.gkseries.com/blog/wp-content/uploads/2023/08/The-total-impedance-of-the-secondary-winding-leads-and-burden-of-a-5-A-CT-is-0.01-Ω.-If-the-fault-current-is-20-times-the-rated-primary-current-of-the-CT.jpg)
Q. The total impedance of the secondary winding, leads, and burden of a 5 A CT is 0.01 Ω. If the fault current is 20 times the rated primary current of the CT, the VA output of the CT is
Solution:
Given that, impedance of secondary winding = 0.01 Ω
Rated current = 5 A
fault current = 20 times of rated current
= 20 × 5 = 100 A
VA output = I2z = 1002 × 0.01 = 100 VA