Q. The total impedance of the secondary winding, leads, and burden of a 5 A CT is 0.01 Ω. If the fault current is 20 times the rated primary current of the CT, the VA output of the CT is
Solution:
Given that, impedance of secondary winding = 0.01 Ω
Rated current = 5 A
fault current = 20 times of rated current
= 20 × 5 = 100 A
VA output = I2z = 1002 × 0.01 = 100 VA
![Determine the correctness (or otherwise) of the following Assertion [A] and the Reason [R]](https://www.gkseries.com/blog/wp-content/uploads/2023/10/Determine-the-correctness-or-otherwise-of-the-following-Assertion-A-and-the-Reason-R.jpg)
