Q. The total length of a cranked bar through a distance D. at 45° in case of a beam of effective length L, is
A. L + (2 × 0.42 d)
B. L – (0.42 d)
C. L – (2 × 0.4 d)
D. L + 0.42 d
Answer: L + (2 × 0.42 d)
We will be happy to hear your thoughts
A. L + (2 × 0.42 d)
B. L – (0.42 d)
C. L – (2 × 0.4 d)
D. L + 0.42 d
Answer: L + (2 × 0.42 d)
