Two equations (I) and (II) are given below. You have to solve both equations and give the answer as.
I. 4×2 – 4x – 35 = 0
II. 2y2 – 17y + 35 = 0
a) x> y
b) y> x
c) x ≥ y
d) x ≤ y
e) x = y or relation cannot be established
Sol:
4×2 – 4x – 35 = 0
4×2 – 14x + 10x – 35 = 0
2x(2x – 7) + 5(2x – 7) = 0
x = -5/2 or 7/2
II.
2y2 – 17y + 35 = 0
2y2 – 10y – 7y + 35 = 0
2y(y – 5) – 7(y – 5) = 0
y = 7/2 or 5
Hence, x ≤ y
