Q. Two numbers are chosen independently and uniformly at random from the set {1, 2 , . . . , 13}. The probability (rounded off to 3 decimal places) that their 4-bit (unsigned) binary representations have the same most significant bit is
Solution:
The 4-bit binary representation of numbers (1, 2, 3, 4………13):
0 – 0000
1 – 0001
2 – 0010
3 – 0011
4 – 0100
5 – 0101
6 – 0110
7 – 0111
8 – 1000
9 – 1001
10 – 1010
11 – 1011
12 – 1100
13 – 1101
There 6 numbers which start with MSB as 1, and 7 numbers which start with MSB as 0.
Therefore, probability that their 4-bit binary representations have the same most significant bit is,
= P(MSB is 0) + P(MSB is 1)
= (7×7)/(13×13) + (6×6)/(13×13)
= (49+36)/169
= 85/169
= 0.5029