NCERT Solutions for class 11 Physics | Chapter 14 - Oscillations

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Questions
1 The period of thin magnet is 4 sec. if it is divided into two equal halves then the time period of each part will be
A 4 sec
B 1 sec
C 2 sec
D 8 sec

Answer:2 sec
2 The bob of a simple pendulum is a spherical hollow ball filled with water. A plugged hall near the bottom of the oscillating bob gets suddenly unplugged. During observation, till water is coming out, the time -period of the oscillation would
A first decrease and then increase to the original value
B first increase and then decrease to the original value
C increase towards a saturation value
D remain unchanged

Answer:first increase and then decrease to the original value
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3 In damped oscilation, the angular frequency of the oscillator
A keeps on decreasing
B keeps on increasing
C emains the same
D fluctuates

Answer:emains the same
4 When a particle performing uniform circular motion of radius 10 cm undergoes the SHM, what will be its amplitude?
A 10 cm
B 5 cm
C 2.5 cm
D 20 cm

Answer:10 cm
5 In damped oscilation the directions of the restoring force and the resistive force
A are the same
B are opposite
C may be same or opposite
D have no relation with each other

Answer:may be same or opposite
6 One of the two clocks on the earth is controlled by a pendulum and other by a spring. If both the clocks are taken to the moon, then which clock will have the same time – period of the earth?
A spring clock
B pendulum clock
C both
D none

Answer:spring clock
7 The displacement y of a particle executing periodic motion is given by y = 4 cos² (t/2) sin (1000t). This expression may be considered to be a result of superposition of the following number of harmonic motions.
A two
B three
C four
D five

Answer:three
8 In the case of forced oscillations, which of the following statements is not true?
A frequency equals that of external periodic force
B amplitude depends upon the damping coefficient
C amplitude tends to infinity at resonance
D higher the damping coefficient, lower is the amplitude at resonance

Answer:amplitude tends to infinity at resonance
9 Spring is pulled down by 2 cm. What is amplitude of motion?
A 0 cm
B 6 cm
C 2 cm
D cm

Answer:2 cm
10 Time period of simple pendulum of length l and a place where acceleration due to gravity is g is T. what is the period of a simple pendulum of the same length at a place where the acceleration due to gravity is 1.029 is,
A T
B 1.02 T
C 0.99 T
D 1.01 T

Answer:0.99 T
11 The acceleration of particle executing S.H.M. when it is at mean position is
A Infinite
B Varies
C Maximum
D Zero

Answer:Zero
12 Length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time – period of the pendulum of increased length is
A 10%
B 1%
C 21%
D 42%

Answer:10%
13 The maximum velocity for particle in SHM is 0.16 m/s and maximum acceleration is 0.64 m/s2. The amplitude is
A 4 × 10-2 m
B 4 × 10-1 m
C 4 × 10 m
D 4 × 100 m

Answer:4 × 10-2 m
14 If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 ms-2 at any time, the angular frequency of the oscillator is equal to
A 10 rad s-1
B 1 rad s-1
C 100 rad s-1
D 1 rad s-1

Answer:10 rad s-1
15 If a hole is bored along the diameter of the earth and a stone is dropped into the hole
A The stone reaches the centre of the earth and stops there
B The stone reaches the other side of the earth and stops there
C The stone executes simple harmonic motion about the centre of the earth
D The stone reaches the other side of the earth and escapes into space

Answer:The stone executes simple harmonic motion about the centre of the earth
16 The period of a simple harmonic oscillator is 2 sec. The ratio of its maximum velocity and maximum acceleration is
A
B 1/∏
C 2∏
D 4

Answer:1/∏
17 If the length of seconds pendulum is increased by 2%, how may seconds it will lose per day?
A 3427 sec
B 3727 sec
C 3927 sec
D 864 sec

Answer:864 sec
18 In SHM, graph of which of the following is a straight line?
A T.E. against displacement
B P.E. against displacement
C Acceleration against time
D Velocity against displacement

Answer:T.E. against displacement
19 The motion of a particle executing simple harmonic motion is given by X = 0.01 sin 100p (t + 0.05), where X is in metres ant t in second. The time period in second is
A 0.001
B 0.02
C 0.1
D 0.2

Answer:0.02
20 For a magnet of time period T magnetic moment is M, if the magnetic moment becomes one fourth of the initial value, then the time period of oscillation becomes.
A Half of initial value
B One fourth of initial value
C Double of initial value
D Four time initial value

Answer:Double of initial value

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