The maximum data rate that a medium of 10 KHz and signal to noise ratio of 30dB is roughly

Answer & Explanation

Option: [B]

Using channel capacity formula of Shannon : we get

C = W * log₂(1 + S/N)

30 dB S/N = 1000 S/N

C = 3000*log₂(1 + 1000)

C = 30 Kbps