Class 12 Chemistry Chapter 2 Solutions MCQs | Class 12 Chemistry Chapter 2 Solutions Objective Type Questions with Answers

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Questions
1 FeCl3 ionizes 80% in their aqueous solution, then what will be the value of Vant ‘Hoff factor i ?
A 4
B 2.7
C 3.4
D 3.1

Answer:3.4
2 CaCl2 ionices 80% in their aqueons solution of 0.2 m CaCl2, then, molality of solution is -
A 0.48 m
B 0.52 m
C 0.6 m
D 2.6 m

Answer:0.52 m
3 A substances associates in their solution as dimer (or bimolecule), then what will be the value of Van’t hoff factor i ?
A 0.2
B 0.4
C 0.6
D All

Answer: 0.6
4 A substance associates as trimer in their solution; then, what would be the value of Van’t Hoff factor i ?
A 0.4
B 0.3
C 0.2
D 0.25

Answer:0.4
5 A substance associates as bimolecule in their solution; then what would be the value of Van’t Hoff factor i ?
A 0.4 d” i < 1
B 0.5 d” i < 1
C 0 < i < 1
D 0.6 d” i < 1

Answer: 0.5 d” i < 1
6 Which of the following ratio is irrelevant formula mass and experimental molecular weight obtained from colligative properties of solution of ionic solid of AB type ?
A 3 : 2
B 5 : 3
C 4 : 3
D 5 : 2

Answer:5 : 2
7 Which of the following ratio of correct molecular wt (formula weight) and experimental molecular weight obtained from colligative properties of solution of ionic solid of AB type is possible ?
A 5 : 3
B 4 : 1
C 7 : 3
D 5 : 2

Answer:5 : 3
8 A substance associates as trimer in their solution, then which of the following ratio is irrelevant for real molecular weight and experimental molecular weight obtained from colligative properties of solution ?
A 2 : 3
B 2 : 5
C 1 : 4
D 1 : 2

Answer:1 : 4
9 Choose the correct option for true and false statement. (For true statement ‘T’ and for false statement ‘F’ is used)
(i) solubility of gas in liquid increases with increase in partial pressure of the gas.
(ii) solubility of gas in liquid increases with increase in temperature
(iii) solubility of gas in liquid isKH is less
(iv) solubility of gas in liquid increases, as partial pressure of gas decreases and temperature increases.
A TTFF
B FTTT
C TFFF
D FFTT

Answer: TFFF
10 Boiling point of an aqueous solution of 0.05m FeCl3 is 100.087 °C; then, what will be the value of Van’t Hoff factor i ? (Kb = 0.513 °C – kg - mole-1)
A 4
B 3.4
C 2.5
D 2.8

Answer: 3.4
11 Difference of boiling point and freezing point of an aqueous solution of glucose is 104 oC at 1 bar pressure; then what will be the molality of the solution ? (Kb = 0.513°C and K+” = 1.86 oC – kg - mole-1)
A 2.373 m
B 1.05 m
C 2.151 m
D 1.68 m

Answer: 1.68 m
12 Difference of boiling point and freezing point of 0.2 m acetic acid prepared in benzene is 75.7 oC ; then, state the value of Van’t Hoff factor i ? (For benzene, Kb = 2.65 °C – kg – mol–1, Kf = 5.12 oC – kg – mol– 1, Tb = 80 oC, Tf = 5.5 oC)
A 1.44
B 0.64
C 0.83
D 0.77

Answer: 0.1 M NaCl
13 Difference in boiling point and freezing point of 10 kg aqueous solution of urea is 100.2372 °C;then what quantity of urea dissolved in the solution ? (Kb = 0.513o and K+” = 1.86 oC – kg - mole-1)
A 59.64
B 38.946
C 51.65
D 40.5

Answer: 59.64
14 500 ml solution of HCl is prepared by dissolving 14.6 gm HCl in water. What will be the molarity of HCl in the solution ? (Molecular weight of HCl = 36.5 gm/mole )
A 0.4 M
B 0.3 M
C 0.8 M
D 0.3 M

Answer:0.8 M
15 What would be the molality of the solution prepared by dissolving 60 gm NaOH in 1.5 kg water ? (Moleculea weight of NaOH = 40 gm/mole)
A 0.5 m
B 1.0 m
C 0.8 m
D 0.4m

Answer:1.0 m
16 What would be the molarity of 3.0 N H2SO4 solution ?
A 6 M
B 1.5 M
C 3 M
D 1 M

Answer: 1.5 M
17 What quantity of NaOH is needed to prepare 1.2 m, 800 ml NaOH solution ?
A 3.84
B 60
C 42
D 38.4

Answer:38.4
18 What would be the molarity and normality of solution prepared by dissolving 19.6 gm H2SO4 in dissolved water to prepare 800 ml solution ? (Molecular weight of H2SO4 is 98 gm/mole)
A 0.5 M, 0.25 N
B 0.25 M, 0.125 N
C 0,25 M, 0.5 N
D 0.125 M, 0.25 N

Answer: 0,25 M, 0.5 N
19 What amount of H2SO4 required to prepare 2 litre of 0.5 N H2SO4solution ? (Molecular weight of H2SO4 is 98 gm/mole)
A 98 gm
B 24.5 gm
C 49 gm
D 73.5 gm

Answer: 49 gm
20 What will be the concentration of solution prepared by dissolving 50 gm glucose in 200 gm water ?
A 25 % w/w
B 20 % w/w
C 35 % w/w
D 15 % w/w

Answer:20 % w/w

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