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NCERT Solutions for class 12 Maths | Chapter 4 - Determinants

(1) The area of a triangle with vertices (-3, 0) (3, 0) and (0, k) is 9 sq. units. The value of k will be
[A] 9
[B] 3
[C] -9
[D] 6
Answer: 3
(2) If A and B are invertible matrices, then which of the following is not correct?
[A] adj A = |A|.A-1
[B] det (a)-1 = [det (a)]-1
[C] (AB)-1 = B-1A-1
[D] (A + B)-1 = B-1 + A-1
Answer: (A + B)-1 = B-1 + A-1

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(3)
[A] 3x² + 4
[B] x(5x + 8)
[C] 3x + 4x²
[D] x(3x + 4)
Answer: x(5x + 8)
(4) If then k =
[A] 0
[B] 1
[C] 2
[D] 3
Answer: 2
(5)
[A] (x³ + y³)²
[B] (x² + y²)³
[C] -(x² + y²)³
[D] -(x³ + y³)²
Answer: -(x³ + y³)²
(6) If x is a complex root of the equation

then x2007 + x-2007 =

[A] 1
[B] -1
[C] -2
[D] 2
Answer: -2
(7)
[A] 2
[B] -2
[C] 4
[D] -4
Answer: -2
(8) If a, b, c are cube roots of unity, then
[A] 0
[B] e
[C] e²
[D] e³
Answer: 0
(9)
[A] 0
[B] 1
[C] 2
[D] 3
Answer: 0
(10) If x > 0 and x ≠ 1. y > 0. and y ≠ 1, z > 0 and z ≠ 1 then

is equal to

[A] 1
[B] -1
[C] 0
[D] None of these
Answer: 0
(11) If Δ = then A =
[A] 0
[B] 10
[C] 12
[D] 60
Answer: 0
(12)
[A] (x – y) (y + z)(z + x)
[B] (x + y) (y – z)(z – x)
[C] (x – y) (y – z)(z + x)
[D] (x – y) (y – z) (z – x)
Answer: (x – y) (y – z) (z – x)
(13) If then the value of x is
[A] ±2
[B] ±1/3
[C] ±√3
[D] ± (0.5)
Answer: ±√3
(14) The determinant equals
[A] abc(b – c)(c -a)(a – b)
[B] (b – c)(c – a)(a – b)
[C] (a + b + c)(b – c)(c – a)(a – b)
[D] None of these
Answer: None of these
(15) If f(x) = then
[A] f(a) = 0
[B] f(b) = 0
[C] f(0) = 0
[D] f(1) = 0
Answer: f(0) = 0
(16) There are two values of a which makes determinant

Δ = = 86, then sum of these number is

[A] 4
[B] 5
[C] -4
[D] 9
Answer: -4
(17)
[A] (a + b)²
[B] (a + b + c + d)²
[C] (a² + b² – c² – d²)
[D] a² + b² + c² + a²
Answer: a² + b² + c² + a²
(18) The value of

is independent of

[A] α
[B] β
[C] α.β
[D] None of these
Answer: α
(19) If x is equal to
[A] 6
[B] ±6
[C] -1
[D] -6
Answer: ±6
(20) The value of the determinant

[A] 124
[B] 125
[C] 134
[D] 144
Answer: 134

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