Q. 10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be
- 4 mL
- 8 mL
- 12 mL
- 16 mL
Answer: 16 mL
