Atomic Structure MCQs

If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

January 8, 2022

14 Views

If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

Q. If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

A. 27.2 eV

B. 40.8 eV

C. 54.4 eV

D. 108.8 eV

Answer: 54.4 eV

If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

Previous

The frequency of light emitted for the transition n = 4 to n = 2 of He+ is equal to the transition in H atom corresponding to which of the following

If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

Next

Bond order of 1.5 is shown by

Related Articles

Wavelength of electron was verified by

Wavelength of electron was verified by

Atom with higher atomic number produces X-rays of

Atom with higher atomic number produces X-rays of

Space around nucleus where finding probability of electrons is maximum is called

Space around nucleus where finding probability of electrons is maximum is called

Quantum number which tells the energy of electron is

Quantum number which tells the energy of electron is

We will be happy to hear your thoughts

Leave a reply Cancel reply

You must be logged in to post a comment.