Multiple Choice Questions and Answers for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure

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Questions
1 Which of the following statements are not correct?
A NaCl being an ionic compound is a good conductor of electricity in the solid-state.
B In canonical structures, there is a difference in the arrangement of atoms.
C Hybrid orbitals form stronger bonds than pure orbitals.
D VSEPR Theory can explain the square planar geometry of XeF4.

Answer:A, B
2 Species having same bond order are :
A N2
B N2-
C F2+
D O2

Answer:C. D
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3 Diamagnetic species are those which contain no unpaired electrons. Which among the following are diamagnetic?
A N2
B N22-
C O2
D O22-

Answer:A, D
4 Which of the following statements are correct about CO32-?
A The hybridisation of the central atom is sp3.
B Its resonance structure has one C–O single bond and two C=O double bonds.
C The average formal charge on each oxygen atom is 0.67 units.
D All C–O bond lengths are equal.

Answer:C, D
5 Which of the following species have the same shape?
A CO2
B CCl4
C O3
D NO2

Answer:C, D
6 CO is isoelectronic with
A NO+
B N2
C SnCl2
D NO2

Answer:A, B
7 Which of the following attain the linear structure:
A BeCl2
B NCO+
C NO2
D CS2

Answer:A, D
8 Which of the following have identical bond order?
A CN–
B NO+
C O2–
D O2

Answer:A, B
9 Amongst the following elements whose electronic configurations are given below, the one having the highest ionisation enthalpy is
A [Ne]3s2 3p1
B [Ne]3s2 3p3
C [Ne]3s2 3p2
D [Ar]3d10 4s2 4p3

Answer:[Ne]3s2 3p3
10 The electronic configuration of the outer most shell of the most electronegative element is
A 2s2 2p5
B 3s2 3p5
C 4s2 4p5
D 5s2 5p

Answer:2s2 2p5
11 Which of the following options represents the correct bond order :
A O2–> O2 > O2+
B O2–< O2 < O2+
C O2–> O2 < O2+
D O2–< O2 > O2

Answer:O2–< O2 < O2+
12 Which of the following statement is not correct from the viewpoint of molecular orbital theory?
A Be2 is not a stable molecule.
B He2 is not stable but He2+ is expected to exist.
C Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.
D The order of energies of molecular orbitals in N2 molecule is σ2s < σ*2s < σ2pz< (π2px = π2py ) < (π*2px= π*2py) < σ*2pz

Answer:The order of energies of molecular orbitals in N2 molecule is σ2s < σ*2s < σ2pz< (π2px = π2py ) < (π*2px= π*2py) < σ*2pz
13 Which of the following order of energies of molecular orbitals of N2 is correct?
A (π2py ) < (σ2pz) < (π*2px) ≈ (π*2py)
B (π2py ) > (σ2pz) > (π*2px) ≈ (π*2py )
C (π2py ) < (σ2pz) > (π*2px) ≈ (π*2py )
D (π2py ) > (σ2pz) < (π*2px) ≈ (π*2py )

Answer:(π2py ) < (σ2pz) < (π*2px) ≈ (π*2py)
14 The bond between B and C will be
A Ionic
B Covalent
C Hydrogen
D Coordinate

Answer: Covalent
15 The molecular formula of the compound formed from B and C will be
A BC
B B2C
C BC2
D BC3

Answer:BC3
16 The stable form of C may be represented by the formula :
A C
B C2
C C3
D C4

Answer:C2
17 The stable form of A may be represented by the formula :
A A
B A2
C A3
D A4

Answer:A
18 Which of the following angle corresponds to sp2 hybridisation?
A 90°
B 120°
C 180°
D 109°

Answer:120°
19 If the electronic configuration of an element is 1s2 2s2 2p6 3s2 3p6 3d2 4s2, the four electrons involved in chemical bond formation will be_____.
A 3p6
B 3p6, 4s2
C 3p6, 3d2
D 3d2, 4s2

Answer:3d2, 4s2
20 In which of the following substances will hydrogen bond be strongest?
A HCl
B H2O
C HI
D H2S

Answer:H2O

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