main()
{
char *x="xyz;
f(k);
printf("%s\n",k);
}
f(char *k)
{
k=malloc(4);
strcpy(k,"pq");
}
What will be the output?
Answer: Option [C]
There is an opening quote in the third statement but no closing. So syntax error occurs.
func(int i)
{
if(i%2) return 0;
else return 1;
}
main()
{
int i=3;
i=func(i);
i=func(i);
printf("%d", i);
}
Answer: Option [B]
| Article and Schedule Quiz | Start Test! |
int Main(int ac, char *av[])
{
if(ac==0) return 0;
else
{
printf("%s", av[ac-1]);
Main(ac-1, av);
}
return 0;
}
Answer: Option [D]
There is no error in the function. Here the Main() function differenciate with the main(). In the given problem the Main() has two arguments as int ac, char *av[]
int fn(int a, int b)
{
if (b==0) return 0;
if (b==1) return a;
return a+fn(a, b-1);
}
Answer: Option [B]
The above function is a recursive function. The function will return a+b where a and b are non-negative integers
main()
{
int a=1, b=10;
swap(a,b);
printf("\n%d%d", a,b);
}
swap(int x, int y)
{
int temp;
temp=x;
x=y;
y=temp;
}
Answer: Option [B]
The 'call by value' method is applied in this program. Here the data is passed by value in the main(). So the variables are not changed.
