Digital Signal Processing Questions and Answers | Digital Signal Processing MCQs

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Questions
1 What is the range of values called as to which the amplitudes of the output during a limit cycle ae confined to?
A Stop band
B Pass band
C Live band
D Dead band

Answer:Dead band
2 Zero input limit cycles occur from non-zero initial conditions with the input x(n)=0.
A True
B False

Answer:True
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3 Which of the following is true when the response of the single pole filter is in the limit cycle?
A Actual non-linear system acts as an equivalent non-linear system
B Actual non-linear system acts as an equivalent linear system
C Actual linear system acts as an equivalent non-linear system
D Actual linear system acts as an equivalent linear system

Answer:Actual non-linear system acts as an equivalent linear system
4 What is the dead band of a single pole filter with a pole at 1/2 and represented by 4 bits?
A (-1/2,1/2)
B (-1/4,1/4)
C (-1/8,1/8)
D (-1/16,1/16)

Answer:(-1/16,1/16)
5 The limit cycle mode with zero input, which occurs as a result of rounding the multiplications, corresponds to an equivalent second order system with poles at z=±1.
A True
B False

Answer:True
6 What is the necessary and sufficient condition for a second order filter that no zero-input overflow limit cycles occur?
A |a1|+|a2|=1
B |a1|+|a2|>1
C |a1|+|a2|<1
D None of the mentioned

Answer:|a1|+|a2|<1
7 An effective remedy for curing the problem of overflow oscillations is to modify the adder characteristic.
A True
B False

Answer:True
8 What is the dead band of a single pole filter with a pole at 3/4 and represented by 4 bits?
A (-1/2,1/2)
B (-1/8,1/8)
C (-1/4,1/4)
D (-1/16,1/16)

Answer:(-1/8,1/8)
9 The ideal low pass filter cannot be realized in practice.
A True
B False

Answer:True
10 The following diagram represents the unit sample response of which of the following filters?

Digital Signal Processing

A Ideal high pass filter
B Ideal low pass filter
C Ideal high pass filter at ω=π/4
D Ideal low pass filter at ω=π/4

Answer:Ideal low pass filter at ω=π/4

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