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NCERT Solutions for class 12 Maths | Chapter 7 - Integrals

(1) ∫ |x| dx is equal to
[A] 1/2 x² + C
[B] –x2/2 + C
[C] x|x| + C
[D] 1/2 x|x| + C
Answer: 1/2 x|x| + C
(2) Evaluate:
[A] log|sec x + tan x| – 2 tan(x/2) + C
[B] log|sec x – tan x| – 2 tan(x/2) + C
[C] log|sec x + tan x| + 2 tan(x/2) + C
[D] None of these
Answer: log|sec x + tan x| – 2 tan(x/2) + C

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(3)
[A] a log |tan-1 x| + C
[B] 1/2(tan-1 x)² + C
[C] a log (1 + x2) + C
[D] None of these
Answer: a log |tan-1 x| + C
(4) Evaluate: ∫ sec4/3 x cosec8/3 xdx
[A] 3/5 tan-5/3 x – 3 tan1/3 x + C
[B] –3/5 tan-5/3 x + 3 tan1/3 + C
[C] –3/5 tan-05/3 x – 3 tan1/3 + C
[D] inversely proportional to the surface area
Answer: None of these
(5) Evaluate: ∫(2 tan x – 3 cot x)² dx
[A] -4tan x – cot x – 25x + C
[B] 4 tan x – 9 cot x – 25x + C
[C] – 4 tan x + 9 cot x + 25x + C
[D] 4 tan x + 9 cot x + 25x + C
Answer: 4 tan x – 9 cot x – 25x + C
(6) dx is equal to
[A] 1
[B] 2
[C] 3
[D] 4
Answer: 4
(7) is equal to
[A]
[B]
[C]
[D]
Answer:
(8) ∫tan-1 √xdx is equal to
[A] (x + 1)tan-1 √x – √x + C
[B] x tan-1 √x – √x + C
[C] √x – x tan-1 √x + C
[D] √x – (x + 1)tan-1 √x + C
Answer: (x + 1)tan-1 √x – √x + C
(9) ∫x² sin x³ dx =
[A] 1/3 cos x³ + c
[B] –1/3 cos x + c
[C] −1/3 cos x³ + c
[D] 1/2 sin² x³ + c
Answer: −1/3 cos x³ + c
(10) dθ =
[A] tan θ – θ + c
[B] θ + tan θ + c
[C] θ – tan θ + c
[D] -θ – cot θ + c
Answer: θ – tan θ + c
(11) dx =
[A] 1 – log 2
[B] 2
[C] 1 + log 2
[D] log 2
Answer: 1 – log 2
(12) What is the value of dx?
[A] 0
[B] π
[C] -π
[D] π/2
Answer: π/2
(13) dx =
[A] log 2
[B] -log 2
[C] log 2 – 1
[D] log 4 – 1
Answer: log 2
(14) What is the value of dx?
[A] 3/2
[B] 1/2
[C] e
[D] 1/e
Answer: 3/2
(15) What is the value of
[A] 1/2 log(-l)
[B] log(- 1)
[C] log 3
[D] log √3
Answer: log 3
(16)
[A] 1
[B] 2
[C] π/4
[D] π2/8
Answer: 2
(17)
[A] -1
[B] 0
[C] 1
[D] None of these
Answer: 0
(18) What is the value of
sin³ x cos² xdx?
[A] 0
[B] 1
[C] 1/2
[D] 2
Answer: 0
(19) dx is equal to
[A] 2 (sin x + x cos θ) + C
[B] 2 (sin x – x cos θ) + C
[C] 2 (sin x + 2x cos θ) + C
[D] 2 (sin x – 2x cos θ) + C
Answer: 2 (sin x + x cos θ) + C
(20) dx =
[A] log(sin x – cos x)
[B] x
[C] log x
[D] log sin (cos x)
Answer: x

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