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NCERT Solutions for class 12 Maths | Chapter 7 - Integrals

(1) dx is equal to
[A] 1
[B] 2
[C] 3
[D] 4
Answer: 1
(2) Evaluate: dx
[A] 1/6 tan-1 (2 tan x) + C
[B] tan-1 (2 tan x) + C
[C] 1/6 tan-1(2tanx/3) + C
[D] None of these
Answer: 1/6 tan-1(2tanx/3) + C

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(3) Evaluate: ∫ sec²(7 – 4x)dx
[A] –1/4 tan(7 – 4x) + C
[B] 1/4 tan(7 – 4x) + C
[C] 1/4 tan(7 + 4x) + C
[D] –1/4 tan(7x – 4) + C
Answer: –1/4 tan(7 – 4x) + C
(4)
[A]
[B]
[C]
[D] None of these
Answer:
(5) Evaluate: dx
[A]
[B]
[C]
[D] None of these
Answer:
(6) ∫ cos(loge.x)dx is equal to
[A] 1/2 x[cos (logex) + sin(logex)]
[B] x[cos (logex) + sin(logex)]
[C] 1/2 x[cos (logex) – sin(logex)]
[D] x[cos (logex) – sin(logex)]
Answer: x[cos (logex) + sin(logex)]
(7) ∫ sin-1 xdx is equal to
[A] cos-1 x + C
[B] x sin-1x ++ C
[C]
[D]
Answer: x sin-1x ++ C
(8) If
[A] a = 1/3, b = 1
[B] a = −1/3, b = 1
[C] a = −1/3, b = -1
[D] a = 1/3, b = -1
Answer: a = 1/3, b = -1
(9) dx is equal to
[A] 2√2
[B] –1/3 cos x + c
[C] 0
[D] 2(√2 – 1)
Answer: 0
(10) dx is equal to
[A] 10x – x10 + C
[B] 10x + x10 + C
[C] (10x – x10)-1 + C
[D] loge(10x + x10) + C
Answer: loge(10x + x10) + C
(11)
[A] √x + k
[B] 2√x + k
[C] x + k
[D]
Answer: 2√x + k
(12)
[A]
[B] log | sin x + cos x | + c
[C] log | sin x – cos x | + c
[D]
Answer: log | sin x + cos x | + c
(13) d/dx ∫f(x)dx is equal to
[A] f'(x)
[B] f(x)
[C] f'(x’)
[D] f(x) + c
Answer: f(x)
(14) What is the value of
[A] π/2
[B] π/4
[C] π/8
[D] None of these
Answer: π/4
(15) is equal to
[A] 1/10010
[B] 1/10100
[C] 1/1010
[D] 1/110100
Answer: 1/10100
(16) ∫log10 xdx =
[A] loge 10.x loge (x/e) + c
[B] log10 e.x loge (x/e) + c
[C] (x – 1) loge x + c
[D] 1/x + c
Answer: log10 e.x loge (x/e) + c
(17)
[A] tan-1 (2x) + c
[B] cot-1 (2x) + c
[C] cos-1 (2x) + c
[D] sin-1 (2x) + c
Answer: sin-1 (2x) + c
(18)
[A]
[B]
[C]
[D]
Answer:
(19) dx is equal to
[A]
[B]
[C]
[D]
Answer:
(20)
[A] log |1 + cotx/2| + C
[B] log |1 – tanx/2| + C
[C] log |1 – cotx/2| + C
[D] log |1 + tanx/2| + C
Answer: log |1 – cotx/2| + C

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