void main(void)
{
char x='\0';
char n='N';
printf("%u""%s\n",&n, &n);
}
What will be the result of execution?
Answer: Option [A]
main()
{
int x=49;
for (;x;)
x--;
printf("%d\n",x);
}
What will be the output of the program?
Answer: Option [B]
For all non-zero values of x the for will execute. x is decremented from 49 to 0. Hence 0 is printed in the screen.
main()
{
int x=3, y=2;
dp(x/y)
}
What will be the output of the program?
Answer: Option [A]
int z,x=5,y=-10,a=4,b=2; z=x++ - --y* b/a;
What will be the final value of z?
Answer: Option [C]
The post increment operator is associated with the variable x. So the current variable is considered i.e. x=5.
The pre increment operator is associated with the variable y. So the value of y decreses by 1. That is y=-11.
Multiplication operator and division operator has the same precedence. So the first one is executed first.
So the expression is:
z=5-(-11)*2/4
=5-(-22/4)
=5-(-5)
=10
short int x; /*assume x is 16 bits in size*/
What is maximum number that can be printed using
printf("%d\n",x);
Answer: Option [D]
By default short integer is signed. 1 bit is reserveed for sign i.e. only 15 bits are available.
So, the largest number will be:
215+214+..........+upto 20
i.e. 32767