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Machine Kinematics Multiple Choice Questions and Answers – Simple Harmonic Motion

(1) The periodic time (tp) is given by
[A] ω / 2 π
[B] 2 π / ω
[C] 2 π × ω
[D] π/ω
Answer: 2 π / ω
(2) The velocity of a particle moving with simple harmonic motion is . . . . at the mean position.
[A] zero
[B] minimum
[C] maximum
[D] none of the mentioned
Answer: maximum

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(3) The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by
[A] ω √r2 − x2
[B] ω √x2 − r2
[C] ω2 √r2 − x2
[D] ω2√x2 − r2
Answer: ω √r2 − x2
(4) The maximum acceleration of a particle moving with simple harmonic motion is
[A] ω
[B] ω.r
[C] ω2.r
[D] ω2/r
Answer: ω2.r
(5) The frequency of oscillation for the simple pendulum is
[A] 1/2π √L/g
[B] 1/2π √g/L
[C] 2π √L/g
[D] 2π√g/L
Answer: 1/2π √g/L
(6) When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as
[A] simple pendulum
[B] torsional pendulum
[C] compound pendulum
[D] second’s pendulum
Answer: compound pendulum
(7) The frequency of oscillation of a compound pendulum is
[A] 1/2π √g.h/k2G +h2
[B] 1/2π √k2G +h2/g.h
[C] 2π√g.h/k2G +h2
[D] 2π√k2G +h2/g.h
Answer: 1/2π √g.h/k2G +h2
(8) The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is
[A] h/ k2G +h2
[B] k2G +h2/h
[C] h2/k2G +h2
[D] k2G +h2/h2
Answer: k2G +h2/h
(9) The centre of percussion is below the centre of gravity of the body and is at a distance equal to
[A] h / kG
[B] h.kG
[C] h2/kG
[D] k2G/h
Answer: k2G/h
(10) The frequency of oscillation of a torsional pendulum is
[A] 2πkG/r √g/I
[B] r/2πkG√g/I
[C] 2πkG/r√I/g
[D] r/2πkG√I/g
Answer: r/2πkG√g/I

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